Physics, asked by ishikagyanee7703, 2 days ago

Two spheres a and b of radii 4 cm and 6 cm given charge of 80 microcoulomb and 20 microcoulomb respectively if these are joined by conducting wire then the charge flow between them will be

Answers

Answered by sarveshsingh7568
0

Answer-q∝

q∝ r

q∝ r1

q∝ r1

q∝ r1 q

q∝ r1 q 1

q∝ r1 q 1

q∝ r1 q 1 r

q∝ r1 q 1 r 1

q∝ r1 q 1 r 1

q∝ r1 q 1 r 1 =q

q∝ r1 q 1 r 1 =q 2

q∝ r1 q 1 r 1 =q 2

q∝ r1 q 1 r 1 =q 2 r

q∝ r1 q 1 r 1 =q 2 r 2

q∝ r1 q 1 r 1 =q 2 r 2

q∝ r1 q 1 r 1 =q 2 r 2

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 =

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 10

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 108×40

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 108×40

q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 108×40 32μC from A to B.

Similar questions