Two spheres a and b of radii 4 cm and 6 cm given charge of 80 microcoulomb and 20 microcoulomb respectively if these are joined by conducting wire then the charge flow between them will be
Answers
Answer-q∝
q∝ r
q∝ r1
q∝ r1
q∝ r1 q
q∝ r1 q 1
q∝ r1 q 1
q∝ r1 q 1 r
q∝ r1 q 1 r 1
q∝ r1 q 1 r 1
q∝ r1 q 1 r 1 =q
q∝ r1 q 1 r 1 =q 2
q∝ r1 q 1 r 1 =q 2
q∝ r1 q 1 r 1 =q 2 r
q∝ r1 q 1 r 1 =q 2 r 2
q∝ r1 q 1 r 1 =q 2 r 2
q∝ r1 q 1 r 1 =q 2 r 2
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 =
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 10
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 108×40
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 108×40
q∝ r1 q 1 r 1 =q 2 r 2 ⇒80μC×4=q 2 (6+4)⇒q 2 = 108×40 32μC from A to B.