Question

Two spheres A and B with masses in the
ratio 2:3 and specific heat 2:3 fall
freely from rest. If the rise in their
temperatures on reaching the ground are
in the ratio 1:2 the ratio of their heights
of fall is?
​

Answer 1

Answer:

Explanation:

as=q=mgh and q=mcdelt

mgh=mcdelt

h=m1c1t1/m2c2t2

=4/18

=2/9

Answer 2

Answer:

1 : 3

Explanation:

mass of A = 2 mass of B = 3

specific heat of A = 2 specific heat of B = 3

rise in temperature of A ( t ) = 1 rise in temperature of B ( t ) = 2

$t = \frac{gh}{js}$

$h = \frac{tjs}{g}$

$\frac{h1}{h2} = \frac{tjs}{tjs}$

$\: \: \: = \frac{1 \times 2}{2 \times 3}$

= 1 : 3

I hope the answer will help you