Physics, asked by javedali2016201, 1 year ago

Two spheres approach each other along the same straight line. Their speeds are u1 and u2
before they collide. After the collision, the spheres separate with speeds v1 and v2 in the
directions shown below.
u1 u2
before collision
v1 v2
after collision
The collision is perfectly elastic. Which equation must be correct?
A u1 – u2 = v2 + v1
B u1 – u2 = v2 – v1
C u1 + u2 = v2 + v1
D u1 + u2 = v2 – v1

Answers

Answered by Fatimakincsem
1

For perfectly elastic collision, both K.E ad momentum are conserved.

Option (D) is correct.

Explanation:

  • Since before collision both spheres are m moving towards each other. the relative speed of approach is the sum of the two speeds.
  • After collision the first sphere is moving towards the second sphere while the second sphere is moving away from the first sphere.
  • If V1 is greater than V2 than it would e approaching the second sphere.
  • If V2 is greater than V1 than it would be moving away from the 1st one.

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Answered by usmanwaj786
0

Answer:

A

Explanation:

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