Two spheres, each of mass m and velocity v are involved in a perfectly inelastic head-on collision. The percentage loss in Kinetic energy due to the collision is
Answers
Answered by
11
Answer:
by conservation of momentum
mv=(3+1)v
f
v
f
=
4
v
loss in kinetic energy=
2
mv
2
−
2
4m(
4
v
)
2
=
8
3mv
2
=
4
3
KE
i
Answered by
1
Answer:
by conservation of momentum
mv=(3+1)vf
vf=4v
loss in kinetic energy=2mv2−24m(4v)2=83mv2=43KEi
hope its help you
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