two spheres having charge q1 seprated by r distance apart experiences electrostatic force F 25% charge of first sphere is transfer to second sphere. find new electrostatic force?
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Initially, the two spheres with charges q1 were separated by a distance of r.
Hence, the electrostatic force according to Coulomb's law will be,
F = kq1²/r²
Now, after the charge transfer, one sphere has charge 3q1/4 (since 25% is transferred from it) while the other sphere has 5q1/4 (since 25% is transferred to it).
Hence, the electrostatic force according to Coulomb's law will be,
F = k(3q1/4)(5q1/4)/r²
F = 15kq1²/16r²
I hope you understand the concept.
If you find it helpful please mark it as brainliest.
All the best!
Hence, the electrostatic force according to Coulomb's law will be,
F = kq1²/r²
Now, after the charge transfer, one sphere has charge 3q1/4 (since 25% is transferred from it) while the other sphere has 5q1/4 (since 25% is transferred to it).
Hence, the electrostatic force according to Coulomb's law will be,
F = k(3q1/4)(5q1/4)/r²
F = 15kq1²/16r²
I hope you understand the concept.
If you find it helpful please mark it as brainliest.
All the best!
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