Two spheres of same metal weigh 1 kg and 7 kg. The radius of the smaller sphere is 3 cm. The two spheres are melted to form a single big sphere. Find the diameter of the new sphere
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M = d V where d is the density of the metal
M1 = 1 kg M2 = 7 kg M3 = M1 + M2 = 8 kg
M = 4/3 pi R^3 d
M3 / M1 = R3^3 / R1^3 since the density doesn't change
R3^3 / R1^3 = M3 / M1 = 8
R3 = 2 R1 solving the above equation for R3
So R3 = 2 * 3 cm = 6 cm
and D3 = 12 cm the diameter of the combined spheres
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