Question

Two spheres separated from each other by 10 m have charges of 0.001 coulomb and 0.003 coulomb respectively. In between the two spheres is a point of zero electric field. What is the distance from the 0.001 coulomb sphereTwo spheres separated from each other by 10 m have charges of 0.001 coulomb and 0.003 coulomb respectively. In between the two spheres is a point of zero electric field. What is the distance from the 0.001 coulomb sphere

Answer 1

Answer:

In between the two spheres is a point of zero electric field. What is the distance from the 0.001 coulomb sphereTwo spheres separated from each ...

Answer 2

Answer:

Explanation:

Concept:

Distance definition:

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Coulomb definition:

The unit of electric charge derived from the SI is the coulomb .  The elementary charge was given the exact value of $1.602176634\times10^{ -19} C$ in the $2019$ redefinition of the SI base units ,making the coulomb exactly $1/(1.602176634\times10 ^{ -19})$ elementary charges.

Charles-Augustin de Coulomb inspired the name of the coulomb. Like every other SI unit named after a person, the word "coulomb" is capitalized at the beginning of a sentence and in titles but otherwise is written in lower case. However, when written in full, the word follows the rules for capitalization of a common noun.

Given:

Distance$(d)$ $=10m$

Charge$(q)$ $=0.001C,0.003C.$

Find:

We have to find the distance from the $0.001$ coulomb sphere.

Solution:

Given that Distance$(d)$ $=10m$

                 Charge$(q)$ $=0.001C,0.003C.$

$\mathrm{E}_{1}=\mathrm{k}_{\mathrm{e}} \mathrm{q} / \mathrm{r}^{2} \therefore\left[\left(8.99 * 10^{9} \mathrm{~N}^{*} \mathrm{~m}^{2} / \mathrm{C}^{2}\right)(0.001 \mathrm{C})\right] /(\mathrm{d})^{2} \\\mathrm{E}_{2}=\mathrm{k}_{\mathrm{e}} \mathrm{q} / \mathrm{r}^{2}:\left[\left(8.99 * 10^{9} \mathrm{~N}^{*} \mathrm{~m}^{2} / \mathrm{C}^{2}\right)(0.003 \mathrm{C})\right] /(10-\mathrm{d})^{2}$

d= the distance that both Electric fields are equal or zero.

You could say that the$0.001 \mathrm{C}$ charge was set at zero on the x-axis and the $0.003$ was $10$ meters away. solve for d in each equation and then set them equal to each other.

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