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two spherical balls of mass 10 kg each are placed with the centres 10 cm apart find the gravitational force of attraction between them?
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Answers

Answered by Λყυѕн
67

\large\underline{ \underline{ \sf \maltese{ \: Correct \: Question:- }}}

Two spherical balls of mass 10kg each are placed with their centers 10cm apart. Find the gravitational force of attraction between them.

\large\underline{ \underline{ \sf \maltese{Given:-}}}

\sf{M_1}{=10kg}

\sf{M_2}{=10kg}

\sf{r=10cm=0.1m}

\large\underline{ \underline{ \sf \maltese{ \: To \: Find:- }}}

Gravitational force between the objects.

\large\underline{ \underline{ \sf \maltese{Solution:- }}}

We know that,

\boxed{\red{\sf{F=G}{\dfrac{m_1m_2}{r^2}}}}

\sf{\green{\implies{F=}{\dfrac{6.67 \times 10^{-11} \times 10\times 10}{0.1 \times 0.1}}}}

\sf{\blue{\longrightarrow{6.67 \times 10^{-7}N}}}

\large\underline{ \underline{ \sf \maltese{ More\:to\:know:- }}}

Universal Law of Gravitation:-

Everything in the universe attracts every other body with a force, which is directly proportional to the product of their masses and inversely proportional to the square of distance between them. The force acts along the line joining the center two bodies.

Mathematically,

\sf{F \propto m_1m_2}

\sf{F \propto}{\dfrac{1}{r^2}}

\sf{\implies}{F \propto}{\dfrac{m_1m_2}{r^2}}

\sf{\longrightarrow}{F=G}{\dfrac{m_1m_2}{r^2}}

Where,

F= Force between the two objects

m1=mass of object 1

m2=mass of object 2

r= horizontal distance between the two objects.

G = Gravitational constant

Main Characteristics of Gravitational force:-

  • The gravitational force is basically a central force, which works along the line joining the centers of two bodies.
  • It is always a long range force. The gravitational force occurs even when we’re talking about large distances.
  • It is a conservative force. This implies that the work which is done by the gravitational force in displacing a body from one point to another is only dependent on the initial and final positions of the body and is independent of the path followed.

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