Question

two spherical balls of mass 20kg each are placed with their center 10 cm apart find gravitational force of attraction between them

Answer 1

Answer:

$\boxed{\mathfrak{Gravitational \ force \ of \ attraction \ (F) = 2.668 \ \mu N}}$

Given:

Mass of each spherical balls (m) = 20 kg

Distance between spherical balls (r) = 10 cm = 0.1 m

Gravitational constant (G) = $\sf 6.67 \times 10^{-11} \ Nm^2kg^{-2}$

To Find:

Gravitational force of attraction (F) between the two spherical balls

Explanation:

Equation of gravitational force of attraction:

$\boxed{ \bold{F = \frac{Gm^2}{r^2}}}$

Substituting value of G, m & r in the equation:

$\sf \implies F = \frac{6.67 \times {10}^{ - 11} \times {20}^{2} }{ {0.1}^{2} } \\ \\ \sf \implies F = \frac{6.67 \times {10}^{ - 11} \times 400}{0.01 } \\ \\ \sf \implies F = \frac{6.67 \times {10}^{ - 11} \times 4 \times {10}^{2} }{ {10}^{ - 2} } \\ \\ \sf \implies F = 6.67 \times 4 \times {10}^{ - 11 + 2 - ( - 2)} \\ \\ \sf \implies F = 26.68 \times {10}^{ - 11 + 4} \\ \\ \sf \implies F = 26.68 \times {10}^{ - 7} \\ \\ \sf \implies F = 2.668 \times {10}^{ - 6} \: N \\ \\ \sf \implies F = 2.668 \: \mu N$

$\therefore$

Gravitational force of attraction (F) between the two spherical balls = 2.668 µN

Answer 2

Answer:

m = 20 kg

r = 0.1 m

G = 6.67 × 10^-11

F = Gm²/r²

By substituting value we get:

F = 26.68 × 10^-7 N