two spherical conductors bnc having equal radii and carrying equal charges in them repel each other with a force f when kept apart at some distance third sperical conductor having the same radius as that of B but uncharged is brought in contact with B then with C and finally removed away from both the new force of repulsion between B and C is
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when 2 identicle metalic surface bought in contact then charge onn them are equalised due to the flow of free elctron
let the initial charge on B and C is q
when third sphere come in contact with B then new charge on B =q/2
and charge on the third conductor =q/2
and third conductor come in contact with C so total charge =q/2 + q =3q/2
charge will equally distribute ,so charge on C = 3q/4
now force = k (q/2)(3q/4) /d2
= 3F/8
let the initial charge on B and C is q
when third sphere come in contact with B then new charge on B =q/2
and charge on the third conductor =q/2
and third conductor come in contact with C so total charge =q/2 + q =3q/2
charge will equally distribute ,so charge on C = 3q/4
now force = k (q/2)(3q/4) /d2
= 3F/8
amit585:
bhai this is correct ans. thnx for ur help
wlcm bro
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