Physics, asked by MiniDoraemon, 5 months ago

Two spring of force constant k₁ and k₂ , are connected to a mass m as shown . the frequency of oscillation of the mass is f . if both k₁ and k₂ are made four times their original values , the frequency of oscillation becomes. [AIEEE 2007]​

Answers

Answered by freedarajesh2003
0

Answer:

Explanation:.

m as shown. The frequency of oscillation of the mass is f . If both k1 and k2 are made four times their original values, the frequency of oscillation becomes. ... Oscillations Due to Spring. Two springs, of force const... physics. Two springs, of force constant k1​ and k2​, are connected to a mass m as shown. The frequency of .

Answered by nehaimadabathuni123
0

This system can be treated as two parallel spring system with spring constants k1 and k2. Now, frequency

f= 1/2π √(k1+k2/m)

When both k1 and k2 are made four times their original value, the new frequency becomes:

f′= 1/2π√(4k1+4k2/m)

= 1/2π 2√(k1+k2/m)

=2f

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