Two springs, each of spring constant k, are attached to a block of mass m as shown in the figure. The block can slide smoothly along a horizontal
platform clamped to the opposite walls of the trolley of mass M. If the block
is displaced by x cm and released, the period of oscillation is
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Given :
Mass of block = m
Mass of trolley = M
Spring constant = k
Displacement = x
To find :
The time period of oscillation = ?
Solution :
- Keff = 2k (As they are parallel)
- Reduced mass = mM/(m+M)
- Time period (T) = 2π×√(M/k)
=2π×√(Mm/(M+m)2k)
=2π×√(Mm/2k(M+m))
The time period of oscillation is 2π×√(Mm/2k(M+m))
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