Question

Two springs have stiffness 5 and 10 respectively are connected in series. Calculate combined stiffness

Answer 1

Answer:

Let resultant stiffness is k.

k1=5,k2=10

1/k=1/k1+1/k2

1/k=1/5+1/10

1/k=3/10

k=10/3.

Answer 2

Answer:

combined stiffness between two springs is $10/3N/m$

Explanation:

Equivalent spring stiffness is calculated using the following formula: stiffness of spring 1*stiffness of spring $2$/(stiffness of spring 1+stiffness of spring $2$).

Keq equals $K1*K2/(K1+K2)$

Three variables make up this formula.

used variables

Equivalent Stiffness of Springs is the single stiffness of spring that is created by combining various spring constants. It is measured in Newton per metre.

The force per unit length necessary to deflect the first spring is known as the stiffness of Spring $1$ (measured in Newton per Meter).

The force per unit length needed to deflect the second spring is known as the stiffness of spring $2$ (measured in Newton per metre).

#SPJ2