Question

Two springs have their respective force constants K1 and K2. Both are stretched till their elastic potential
energies are equal. If the stretching forces are F1 and F2 find F1/ F2​

Answer 1

Answer:

Let x1 and x2 are stretches in springs.

Potential enery ratio =u1/u2=(1/2*k1*x1^2)/(1/2*k2*x2^2)

u1/u2=1=k1/k2*(x1/x2)^2

x1/x2=root(k2/k1)

Now, force ratio

F1/F2=k1x1/k2x2=root(k1/k2)

Answer 2

Answer:

hope it helps u sir ❤❤❤❤❤❤❤❤