Question

Two springs of spring constant 1500N/m and 3000N/m respectively are stretched with same force. they will have potential energies in the ratio

Answer 1

PE = 1/2  k x^2  = 1/2 k (F/k)^2 = 1/2 F^2 / k

since F is same,  k is in the denominator,
ratio :  2 : 1

Answer 2

Answer:

Explanation:

Here is your answer