Two springs s1 and s2 have negligible masses and the spring constant of s1 is one-third that of s2. When a block is hung from the springs as shown, the springs came to the equilibrium again.Find the ratio of work done is stretching s1 to s2.
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given = S1 and S2 are springs.
to find = ratio of work done when stretching S1 and S2.
solution,
as per diagram the springs are attached in series combination, so force on each spring on S1 and S2 will be F1 & F2 respectively.
F1 = F2
F1 /F2 =1
The ratio of work done is 1 : 1
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the ratio of work done in stretching s1 to s2 is 1:1
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