Question

Two springs with spring constants 30 N/m and 10 N/m are added in series, and a weight of 36 N is suspended from them. What is the extension of the spring system?

Answer 1

Answer: X = 4.8

Explanation: you use the formula F=K x X

then they gave you the spring constant which are 30N/m and 10N/m

so you needs to find K total which you use K1 x K2/ K1 + K2

which is 30 X 10/ 30 +10 = 7.5 K

then u added it in the formula

You already got 36N u just put it in

36= 7.5 x X         u divide 36/7.5

and your final answer for the extension is 4.8

Answer 2

Given: Two springs with spring constants 30 N/m and 10 N/m are added in series, and a weight of 36 N is suspended from them.

To find: Extension of the spring system

Solution:

• The extension of each spring in the series can be found using Hooke's Law: F = kx, where F is the force applied, k is the spring constant, and x is the extension.
• The total force applied to the spring system is equal to the weight of the suspended object, which is 36 N.
• The total spring constant of the two springs in series is equal to the sum of the spring constants of each spring, which is 30 N/m + 10 N/m = 40 N/m.
• Using the total spring constant and the applied force, the extension of the spring system can be found as x = F/k = 36 N/40 N/m = 0.9 m.
• Therefore, the extension of the spring system is 0.9 m.

To learn more about extension from the given link.

https://brainly.in/question/54998874

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