Math, asked by pragya48, 1 year ago

two sprinter run the same race of 100 meters. one run at a speed of 10 meters per second and the other run at 8 meters per second. by what time will the first sprinter beat the other sprinter

Answers

Answered by Uditraj9
112
Distance =100m
Speed of 1st= 10m/sec
Time =100÷10=10sec

Speed of second=100÷8
=12.5sec
first sprinter beat the other sprinter by 12.5sec-10sec=2.5sec
Answered by Anonymous
24

Answer:

2.5 seconds

Step-by-step explanation:

Distance to complete the race = 100m  (Given)

Number of sprinters = 2 (Given)

Speed of the first sprinter = 10m/sec  (Given)

Speed of the second sprinter = 8m/sec  (Given)

Thus, the time taken by first sprinter = 100÷10 = 10sec

Thus, the time taken by the second sprinter = 100÷8  = 12.5sec

Difference between both the sprinters =12.5 - 10

= 2.5

Therefore, first sprinter beat the other sprinter by 2.5 seconds

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