two sprinter run the same race of 100 meters. one run at a speed of 10 meters per second and the other run at 8 meters per second. by what time will the first sprinter beat the other sprinter
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Answered by
112
Distance =100m
Speed of 1st= 10m/sec
Time =100÷10=10sec
Speed of second=100÷8
=12.5sec
first sprinter beat the other sprinter by 12.5sec-10sec=2.5sec
Speed of 1st= 10m/sec
Time =100÷10=10sec
Speed of second=100÷8
=12.5sec
first sprinter beat the other sprinter by 12.5sec-10sec=2.5sec
Answered by
24
Answer:
2.5 seconds
Step-by-step explanation:
Distance to complete the race = 100m (Given)
Number of sprinters = 2 (Given)
Speed of the first sprinter = 10m/sec (Given)
Speed of the second sprinter = 8m/sec (Given)
Thus, the time taken by first sprinter = 100÷10 = 10sec
Thus, the time taken by the second sprinter = 100÷8 = 12.5sec
Difference between both the sprinters =12.5 - 10
= 2.5
Therefore, first sprinter beat the other sprinter by 2.5 seconds
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