Question

Two sprinters run the same race of 200 metres. One runs at a speed of 10 metres per second and
the other runs at 8 metres per second. By what time will the first sprinter beat the other sprinter?​

Answer 1

Answer:

5 seconds

Step-by-step explanation:

Given ,

S(first sprinter )=10 m/s

D =200m

Therefore,

T=D/T

T=200/10

T=20seconds

thus , 1 sprinter take 20 second .

for second sprinter ,

S=8m/s

T=200/8

T=25seconds

thus , 2 sprinter take 25 second

Difference = 5 seconds

Therefore , the first sprinter beats the second by a time gap of 5 seconds.

Answer 2

$\bf{\huge{\underline{\boxed{\tt{\red{Answer:}}}}}}$

Given :-

• Two sprinters run the same race of 200 metres, Distance = 200 m
• One runs at a speed of 10 metres per second, $\bf{Speed_1}$ = 10 m/s
• The other runs at 8 metres per second, $\bf{Speed_2}$ = 8 m/s

To find :-

• Time by which the first sprinter will beat the second sprinter.

Sóĺúťíóń :-

We have 2 sprinters running a race of 200 m with two different speeds. As per the question, the winner is the first sprinter.

Let's begin now!

We know that distance is calculated by the formula,

Speed = $\bf\frac{Distance}{Time}$

Here, we have speed and distance, but need to find the time. So we will formulate the formula for time.

Time = $\bf\frac{Distance}{Speed_1}$

For second sprinter :-

Time = $\bf\frac{200}{10}$

$\bf{ <strong>Time</strong>_1}$ = 20 sec

•°• Time taken by the second sprinter to complete the race of 200 m with a speed of 10 m/s is 20 sec.

For first sprinter :-

Time = $\bf\frac{Distance}{Speed_2}$

Time = $\bf\frac{200}{8}$

$\bf{<strong> </strong><strong>Time</strong>_2<strong> </strong>}$ = 25 sec

The time by which the first sprinter beat the other sprinter will be the difference of the time taken by both the sprinter.

Time taken by first sprinter = 25 second

Time taken by other sprinter = 20 second

=> $\bf{ Time_1}$ - $\bf{ Time_2 }$

=> 25 - 20

=> 5

•°• Time by which the first sprinter beat the other sprinter is 5 seconds