Question

two squaes have side x cm and x+5 cm

Answer 1

Answer:

Step-by-step explanation:

Let A1 & A2 be two squares .

Given : side of square A1= x cm

side of square A2=( x +4 ) cm

Area of square A1 = side × side = x× x= x²

Area of square A2 = side × side = (x+4)× (x+4) =(x+4)²=  x²+8x +16

[(a+b)² = a² +2ab +b²]

Area of square A1 + Area of square A2 = 656 ( GIVEN)

x² + x²+8x +16 = 656

2x² +8x +16 = 656

2x² +8x = 656 -16

2x² +8x = 640

2x² +8x - 640= 0

2(x² +4x -320)= 0

x² +4x -320 = 0

x² + 20x -16x -320= 0

x( x +20) - 16(x +20)= 0

The length of the side of a square cannot be negative. Therefore x = 16 .

side of square A1= x cm = 16 cm

side of square A2=( x +4 ) cm = 16 +4= 20 cm

Hence, side of square A1= 16 cm &

side of square A2= 20 cm.

HOPE THIS WILL HELP YOU..