Question

Two square plates are at p.d of 100V separated
by 2 cm. Find intensity between them​

Answer 1

Answer:-

• Potential difference=V=100V
• Area=A=2cm^2
• Intensity=E=?

We know that

$\boxed{\sf E=\dfrac{V}{A}}$

$\\ \sf\longmapsto E=\dfrac{100}{2}$

$\\ \sf\longmapsto E=50V/cm^2$