Two squares each of side 19cm are placed side by side without any gap.find the (¡)perimeter (¡¡)area of the rectangle formed
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Answered by
3
Length of rectangle, L = 19+19 = 38
Breadth of rectangle, B = 19
i) Perimeter = 2(L+B) = 114
ii) Area = LB = 722
Breadth of rectangle, B = 19
i) Perimeter = 2(L+B) = 114
ii) Area = LB = 722
Answered by
3
Answer:
Length of squares = 19cm+19cm = 38cm
Breadth of squares= 19cm
(i) Perimeter of squares = 2× (l+b)
= 2× (38cm + 19cm)
= 2× 57
= 114cm
(ii) Area of squares = l×b
= 38cm × 19cm
= 722cm
Step-by-step explanation:
So, here we have written the length of squares = 38cm because the question is that two squares are kept together without gap so we will double the length
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