Two squares have sides p cm and p+5 cms. the sum of their squares is 625sq.cm
Answers
Answered by
2
(p)^2+(p+5)^2
=625 cm^2
(p)^2+p^2+5^2+2*5p=p^2+p^2+25+10p
=2p^2+25+10p=625
=2p^2+10p=625-25
=2p^2+10p=600
=2p+10p=root 600
=12p=root 600
=p=root 600/12
=p=root600/root12*root12
=p=root 50/root 12
=p=root 12.5/root 3
=p=root 4.17
=p=2.042 cm
=625 cm^2
(p)^2+p^2+5^2+2*5p=p^2+p^2+25+10p
=2p^2+25+10p=625
=2p^2+10p=625-25
=2p^2+10p=600
=2p+10p=root 600
=12p=root 600
=p=root 600/12
=p=root600/root12*root12
=p=root 50/root 12
=p=root 12.5/root 3
=p=root 4.17
=p=2.042 cm
Answered by
2
Answer:
p 1 = 15 & p 2= 20
Step-by-step explanation:
p = -20 will not be considered because length can't be negative
Attachments:
Similar questions