Question

Two squares have siđes x cm and (2x+1) cm,
respectively. The sum of their perimeters is
100 cm. Area (in cm?) of the bigger square is
(b) 289
(c) 64 (d) 81
(a) 225
with full solution ​

Answer 1

Answer:

Explanation:

Given :

• Two square have sides x cm and (2x + 1) cm.
• Sum of their perimeters is 100 cm.

To Find :

• Area of the bigger square.

Solution :

We know,

Perimeter of square = 4 × side

Given that, Sum of their perimeters is 100 cm.

.°. Perimeter of smaller square + Perimeter of bigger square = 100

=> 4(x) + 4(2x + 1) = 100

=> 4x + 8x + 4 = 100

=> 12x = 100 - 4

=> 12x = 96

=> x = 96/12

=> x = 8

So,

Side of smaller square = x = 8 cm

Side of bigger square = (2x + 1) = (2×8 + 1) = 17 cm

We know,

Area of square = side²

Now,

=> Area of bigger square = 17²

=> Area of bigger square = 289 cm²

Hence :

The area of bigger square is 289 cm².

Answer 2

Answer:

a

Step-by-step explanation:

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