two squares of area 16cm square and 36cm square are placed adjacent to each other to form a new shape the perimeter
Answers
Answer:
Perimeter of The New Shape = 32cm.
SOLUTION
Let us Assume that the First Square is ABCD.
Let us Assume that the second Square is PQRS.
GIVEN :-
Area of First Square ABCD = 16cm².
Area of Second Square PQRS = 36cm².
SQUARE ABCD
Area of a Square = a²( a is the side)
16 = a²
a = √16 = 4
★ Side (a) of the First Square ABCD = 4cm.
SQUARE PQRS
Area of a Square = a²( a is the side)
36 = a²
a = √36 = 6
★ Side (a) of the second square PQRS = 6cm.
Perimeter of the new figure formed on placing these two squares adjacent to each other = Perimeter of Square ABCD - 4cm + Perimeter of Square PQRS - 4cm.
Perimeter of ABCD
Perimeter of a square = 4a ( a is the side)
Here,
Side (a) = 4cm.
Perimeter of Square ABCD = 4 × 4 = 16cm.
Perimeter of PQRS
Perimeter of a square = 4a ( a is the side)
Here,
Side (a) = 6cm.
Perimeter of Square PQRS = 4 × 6 = 24cm.
Perimeter of The New Shape = 16 - 4 + 24 - 4 = 12 + 20 = 32cm.
Given : two squares of area 16cm square and 36cm square are placed adjacent to each other to form a new shape
To Find : the perimeter of new shape
Solution:
squares of area 16cm square
=> Side of Square = √16 = 4 cm
Perimeter of Square = 4 * 4 = 16 cm
squares of area 36cm square
=> Side of Square = √36 = 6 cm
Perimeter of Square = 4 * 6 = 24 cm
Square are placed adjacent to each other to form a new shape
Side of 4 cm of Square will be touching side of square of 6 cm
Hence 4 cm will be subtracted from each perimeter
16 - 4 + 24 - 4 = 32 cm
or add perimeter as shown in figure
= 4 + 6 + 6 + 6 + 2 + 4 + 4
= 32 cm
the perimeter of new shape = 32 cm
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