two squares of maximum size were obtained from one rectangle
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→ L = 2S . therefore, → L = 2B . hence, we can conclude that, length of the rectangle will be twice to its breadth .
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For example: If the rectangle is of size 6×96×9. We can cut it into 54 squares of size 1×11×1, 00 of size 2×22×2, 66 of size 3×33×3, 00 of size 4×44×4, 00 of size 5×55×5 and 00 of size 6×66×6. The minimum number of squares of maximum size that can cut is 66.
My approach: I computed the product m×nm×n say KK.Then found the maximum perfect square that divides KK. The quotient of this division seems to be the required answer. But unfortunately it's doesn't seem to yield correct answer. Where exactly I am going wrong?
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