Question

. Two states of energy gap 6.9x10-21J have relative
Probability of e2. Calculate the temperature of the complete system.

Answer 1

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Answer 2

Given :

Two state of energy gap , $E_2-E_1=6.9\times 10^{-21}\ J$ .

Also , relative probability , $P=e^2$ .

To Find :

The temperature of the complete system .

Solution :

We know , relative probability is given by :

$P=e^{(\dfrac{E_2-E_1}{kT})}\\\\e^2=e^{(\dfrac{E_2-E_1}{kT})}$

Comparing , power of e .

We get :

$\dfrac{E_2-E_1}{kT}=2$

Here , k is Boltzmann's constant , $k=1.38\times 10^{-23}\ m^2\ kg\ s^{-2}\ K^{-1}$

Putting all value in above equation :

We get :

T = 250 K .

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