Two stationary sources each emit waves of
wavelength 2. An observer moves from one source
to another with velocity u. Then number of beats
heard by him
(1)2u/lambda
(2)u/lambda
(3)
(4)u/2lambda
Attachments:
Answers
Answered by
2
Answer:
this is your answer
thank you
Attachments:
Answered by
1
Answer:
(2) u / λ
Explanation:
wave speed : v
source speed : vs = 0
original frequency : n
apparent frequency ( approach ) : n'
apparent frequency ( away ) : n"
observer speed : u
formula 1 v = nλ
hence....n = v/λ = v/2λ ( given that 2λ )
formula 2 : f' = f × ( v ± u ) / ( v ± vs )
hence....
n' = v/2λ ( v + u ) / ( v - 0 )
n" = v/2λ ( v - u ) / ( v - 0 )
now ...
beats = n' - n"
= [ v/2λ ( v + u ) / v ] - [ v/2λ ( v - u ) / v ]
= v/2λ ( 2u/v )
= u / λ
Similar questions
Computer Science,
3 months ago
Social Sciences,
3 months ago
English,
7 months ago
English,
7 months ago
Political Science,
11 months ago
Science,
11 months ago
Math,
11 months ago