Two stones A and B are dropped from the top of two different tower such that they travel 44.1 M and 63.7 M in last second of their motion respectively find the ratio of the height of the two Towers from where the stones were dropped
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We will use the kinematics equation below :
V² = U² + 2as
Where :
V = Final velocity
U = initial velocity
a = acceleration due to gravity = 10m/s²
The initial velocity for both A and B is 0
CALCULATIONS for :
A :
V = 44.1 / 1 = 44.1 m/s
44.1² = 0 + 2 × 10 × S
1944.81 = 20S
S = 1944.81/20 = 97.24
B :
V = 63.7
63.7² = 0 + 2 × 10 × S
20 S = 4057.69
S = 4057.69 / 20 = 202.88M
The ratio of the two towers is thus :
202. 88 / 97.24 = 2.086
V² = U² + 2as
Where :
V = Final velocity
U = initial velocity
a = acceleration due to gravity = 10m/s²
The initial velocity for both A and B is 0
CALCULATIONS for :
A :
V = 44.1 / 1 = 44.1 m/s
44.1² = 0 + 2 × 10 × S
1944.81 = 20S
S = 1944.81/20 = 97.24
B :
V = 63.7
63.7² = 0 + 2 × 10 × S
20 S = 4057.69
S = 4057.69 / 20 = 202.88M
The ratio of the two towers is thus :
202. 88 / 97.24 = 2.086
Answered by
3
Answer:
Explanation:
We will use the kinematics equation below :
V² = U² + 2as
Where :
V = Final velocity
U = initial velocity
a = acceleration due to gravity = 10m/s²
The initial velocity for both A and B is 0
CALCULATIONS for :
A :
V = 44.1 / 1 = 44.1 m/s
44.1² = 0 + 2 × 10 × S
1944.81 = 20S
S = 1944.81/20 = 97.24
B :
V = 63.7
63.7² = 0 + 2 × 10 × S
20 S = 4057.69
S = 4057.69 / 20 = 202.88M
The ratio of the two towers is thus :
202. 88 / 97.24 = 2.086
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