Question

Two stones are projected from the top of a tower in opposite directions, with the same velocity V but at 300& 600 with horizontal
respectively. The relative velocity of first stone relative to second stone is
(A) 2V
(B)
V2V
(C)
2V
V3
(D
)
V
V2​

Answer 1

Answer:

√2v

Explanation:

As seen in figure,

 For x direction,

       v₁ - v₂ =  $\frac{1}{2} v - \frac{\sqrt{3}v}{2} ~(+i)$

       v₁ - v₂ =  $\frac{(1-\sqrt{3})v}{2}}~(+i)$

 For y direction,

       v₁ - v₂ =  $\frac{1}{2} v + \frac{\sqrt{3}v}{2} ~(-j)$

       v₁ - v₂ =  $\frac{(1+\sqrt{3})v}{2}}~(-j)$

And then you have to find vector sum of the velocity components.

By doing above procedure,

You'll get answer √2 × v