Question

two stones are projected from the top of Tower in opposite directions with same velocity v at angle 30 degree and 60 degree to the horizontal the relative velocity of an stone respect to other is​

Answer 1

Answer:

please check attachment

Explanation:

Answer 2

Given :

Stone 1 : $|V_a| = v ,$ thrown at an angle of $30$ degree from horizontal.

Stone 2 : $|V_b| = v ,$ thrown at an angle of $60$ degree from horizontal in other direction.

To Find :

$V_a - V_b$

Explanation:

$V_a = vcos30^{\circ} \hat i + vsin30^{\circ} \hat j\\V_b = -vsin60^{\circ} \hat i + vsin60^{\circ} \hat j\\V_a - V_b = vcos30^{\circ} \hat i + vsin30^{\circ} \hat j + vsin60^{\circ} \hat i - vsin60^{\circ} \hat j\\V_a - V_b = \sqrt{3} v \hat i + \sqrt{\frac{1}{3} } v \hat j$

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