Question

two stones are projected horizontally from the top of a tower of height 78.4 m with velocities 25m/s and 45m/s the separation between them on reaching the ground, if both are projected same in the direction​

Answer 1

Explanation:

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Answer 2

Answer:

80 m

Explanation:

R1 = u1 $\sqrt[2]{\frac{2h}{g} }$

   = 25 * ( $\frac{2 * 74.8}{9.8}$) ^ 1/2                     {sqrt of 2h/g}

   = 25 * $\sqrt{16}$

   = 25 * 4

R1 = 100 m

R2 = u2$\sqrt[2]{\frac{2h}{g} }$

     = 45 * ( $\frac{2 * 74.8}{9.8}$) ^ 1/2

     = 45 * $\sqrt{16}$

     = 45 * 4

R2 = 180 m

Distance between both stones = R2 - R1 = 180 - 100 = 80 m