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Two stones are projected in air each
with a speed v, at angles 8 and 0, (both
acute), to the horizontal. If the maximum
height reached by the first stone is more
than that due to the second stone (if H,>
H), then find the wrong option from the
following
1) angle of projection (0,>0.)
2) time of flight (T,>T,)
3) horizontal range R may be equal to,
greater than or less than R,
4) angle of projection(0,<0.)
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Answer:
Correct answers...
H1 = v^2 sin^2 (theta) / 2g
Only depends on theta v and g are same
As H1 is more so...
Theta 1 > Theta 2
So time of flight 1 > time of flight 2
Explanation:
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