Question

Two stones are projected with the same speed, but are making different angles with the horizontal. their horizontal ranges are equal. the angle of projection of one is π/3 and the maximum height reached by it is 102 m. the maximum height reached by the other in metre is

Answer 1

The Range of projectles is same for complementary angles that for Q and 90-Q

Use the formula H=usquare sinsquareQ/2g to calculate max. Height. Use Q=30 degree

Answer 2

Answer:

34

Step-by-step explanation:

We have given pi/3 angle of first ball.

so the angle will be 60°.

so another angle would be (90-60)=30°

Now,(u^2sin^2(60))/2(g)=

(u^2sin^2(30))/2(g)

=1/3

so,H1=102

H2=102/3

H2=34