Question

Two stones are thrown from the top of a tower, one straight
down with an initial speed u and the second straight up
with the same speed u. When the two stones hit the ground,
they will have speeds in the ratio
(a) 2 : 3 (b) 2 : 1
(c) 1 : 2 (d) 1 : 1

Answer 1

Answer:

2:1 is your answer

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Answer 2

In case of stone thrown downwards, initial velocity,u=u

So, using equation v

2 −u 2

=2aS,

here, u=u,v=0,a=a,S=Distance

So, final equation=u 2

=2aS......(1)

Again, for stone thrown upwards, initial velocity,u=−u

So, using equation v

2 −u 2

=2aS,

here, u=−u,v=0,a=a,S=Distance=S

So, final equation=u 2

=2aS.......(2)

Dividing (1) by 2, we get ratio of $\sf\pink{ 1:1}$

In both the cases,(u is positive or negative)u 2

$\huge \tt \underline \orange {is \:positive }$