Question

Two stones are thrown simultaneously from the same point with equal speed v° at an angle 30°and 60° respectively with the positive axis. The velocity with which the stones move relative to each other in air is

Answer 1

Stone 1 is thrown at an angle of $30^{o}$. Therefore, the x-axis component of the velocity is $vcos(\theta)  = vcos(30^{o}) = \frac{\sqrt{3} }{2}v.$

Stone 2 is thrown at an angle of $60^{o}.$ Therefore, the x-axis component of the velocity is $vcos(\theta)  = vcos(60^{o}) = \frac{1 }{2}v.$

Since the two stones move in the same direction, the relative velocity is the difference between the two velocities; which is $\frac{\sqrt{3} }{2}v-\frac{1}{2}v = 0.366v$