Question

Two stones are thrown towards each other simultaneously, one vertically downwards from the top of the

tower of height 360 m with velocity 10 m/s and other from the ground vertically upwards with velocity

50 m/s. Find the time and the distance from the ground at which they collide. [Take, g = 10 m/s2

]

plzz answer fast ​

Answer 1

Answer:

In case of stone thrown downwards, initial velocity,u=u

So, using equation v

2

−u

2

=2aS,

here, u=u,v=0,a=a,S=Distance

So, final equation=u

2

=2aS......(1)

Again, for stone thrown upwards, initial velocity,u=−u

So, using equation v

2

−u

2

=2aS,

here, u=−u,v=0,a=a,S=Distance=S

So, final equation=u

2

=2aS.......(2)

Dividing (1) by 2, we get ratio of 1:1

In both the cases,(u is positive or negative)u

2

is positive.

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