Question

Two stones are thrown towards each other simultaneously, one vertically downwards from the top of the

tower of height 360 m with velocity 10 m/s and other from the ground vertically upwards with velocity

50 m/s. Find the time and the distance from the ground at which they collide.[Take, g = 10 m/s2]

​

Answer 1

Answer:

While both the stones are in flight, a

1

=g and a

2

=g

So a

rel

=0⇒V

rel

=constant

⇒X

rel

=(const)t

⇒Curve ofx

rel

v/s t will be straight line.

After the first particle drops on ground, the seperation (x

rel

) will decrease parabolically (due to gravitational acceleration),

and finally becomes zero.

and V

rel

=slope of x

rel

v/st

solution