two stones are thrown towards each other simultaneously one vertically downward from the top of the tower of height 360 m with velocity 10 m/s and other from groung verticlly upward with veocity 50 m/s find the time and the distance from the ground at which they collide take g=10 m/s^2
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Answer:
5s is the correct answer
Explanation:
Time to reach maximum height can be obtained from v=u+at
0=20+(−10)t
t=2s
s=ut+0.5at
2
=20(2)+0.5(−10)(2)
2
=20m
Thus, total distance for maximum height is 45 m
s=ut+0.5at
2
45=0+0.5(10)(t
′
)
2
t
′
=3s
Total time= 3+2= 5s
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