Question

Two stones are thrown vertically upward with speed 30 m/s and 40 m/s from two points on a horizontal ground separated by a distance of 40 m. The distance between the two stones at time t = 3 s after projection is

30 m

75 m

60 m

50 m​

Answer 1

Explanation:

PARTICLE 1

v= 30 m/s

g = -10m/s^2

equation of motion

s = ut + 1/2at^2

s = 30× 3 - (1/2 ×10 ×3×3)

s = 90 - 45

s1 = 45m

PARTICLE 2

s = ut - 1/2 at^2

s = 40×3 - (1/2 ×10×3×3)

s = 120 - 45

s = 75 m

distance between two stones is 30m