two stones are thrown vertically upwards simultanelously with their initial velocities u1 and u2 respectively. Prove that the heights reached by then would be in ratio of u12:u22 (assume upward acceleration is -g and downward acceleration to be g+)
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Answered by
8
as stones are thrown in upward direction,
u1=
a=-10m/s2
v=0m/s
u2
a=-10m/s2
v=0m/s
hii here is ur ans
pls mark as brainliest
#follow...........
u1=
a=-10m/s2
v=0m/s
u2
a=-10m/s2
v=0m/s
hii here is ur ans
pls mark as brainliest
#follow...........
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thnku frnd
wlcum
pls mark as brainliest
Answered by
5
v=u+at,
here v=u-gt
v=0
u=gt
t=u/g
now s=ut -1/2gt^2
s1=u1×u/g-1/2u1^2/g
=1/2u1^2g
similarly
s2=1/2u2^2/g
s1/s2=u1/u2
(proved) for any doubt you can ask me again.
here v=u-gt
v=0
u=gt
t=u/g
now s=ut -1/2gt^2
s1=u1×u/g-1/2u1^2/g
=1/2u1^2g
similarly
s2=1/2u2^2/g
s1/s2=u1/u2
(proved) for any doubt you can ask me again.
sry sry u1^2/u2^2
okk... thnku for answering
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