Physics, asked by KaavyaBhatia1234, 11 months ago

Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them
would be in the ratio of u 2: u 2 ( Assume upward acceleration is –g and 12 downward acceleration to be +g )

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Answers

Answered by radhikaeee2001
1
  1. Given, initial velocities: u₁ and u₂
  2. g=acceleration due to gravity, here it is (-g), as the object is thrown vertically upwards
  3. Let Final velocities: v₁ and v₂
  4. Now, we know that, 
  5. For object 1:
  6. Putting v=0
  7. ..................(i)
  8. Similarly for object 2:
  9. ......................(ii)
  10. Divide (i) by (ii)
  11. Therefore,
  12. Hence Proved
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