Two stones are thrown vertically upwards simultaneously with their initial velocities u1 and u2 respectively. Prove that the heights reached by them
would be in the ratio of u 2: u 2 ( Assume upward acceleration is –g and 12 downward acceleration to be +g )
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- Given, initial velocities: u₁ and u₂
- g=acceleration due to gravity, here it is (-g), as the object is thrown vertically upwards
- Let Final velocities: v₁ and v₂
- Now, we know that,
- For object 1:
- Putting v=0
- ..................(i)
- Similarly for object 2:
- ......................(ii)
- Divide (i) by (ii)
- Therefore,
- Hence Proved
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