Question

Two stones are thrown vertically upwards simultaneously with their initial velocities
U1and u2 respectively. Prove that the heights reached by them would be in the ratio u1:u2
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Answer 1

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Given, initial velocities: u₁ and u₂

g=acceleration due to gravity, here it is (-g), as the object is thrown vertically upwards

Let Final velocities: v₁ and v₂

Now, we know that,

s= \frac{v^2-u^2}{2g}

For object 1:

s_1= \frac{v_1^2-u_1^2}{-2g}

Putting v=0

s_1= \frac{-u_1^2}{-2g}= \frac{u_1^2}{2g} ..................(i)

Similarly for object 2:

s_2= \frac{u_2^2}{2g} ......................(ii)

Divide (i) by (ii)

\frac{s_1}{s_2} = \frac{ (\frac{u_1^2}{2g} )}{ (\frac{u_2^2}{2g}) }

Therefore,

\frac{s_1}{s_2}= \frac{u_1^2}{u_2^2} \ or \ u_1^2:u_2^2

Hence Proved

Answer 2

Answer:

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