Question

Two stones are thrown vertically upwards simultaneously with their initial velocity U1 and U2 respectively. Prove that the height reached by them would be in the ratio of U^21:U^22

Answer 1

Explanation:

Use third equation of motion.

1st stone:

u=u₁

v=0 (at top)

v²-u₁² =  -2gh₁

0-u₁²= -2gh₁

h₁= u₁²/2g

2nd stone:

u=u₂

v=0 (at top)

v²-u₂² =  -2gh₂

0-u₂²= -2gh₂

h₂= u₂²/2g

h₁/h₂= u₁²/u₂²

Proved.