two stones are thrown verticallyvupwards
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By using the formula
2as = v² - u²
Here v would be zero at maximum height. Hence v² = 0
=> 2as = -u²
s= -u²/2a
Height = s
Height of stone 1 :-
s1 = -u1²/-2g

Since a = -g
2a = -2g
Height of stone 2 :-
s2 =

ratio of s1 and s2 =
-u1²/-2g : -u2²/-2g
Cancelling -2g we have ratio =
-u1²: -u2²
Cancelling negative sign we have
u1² : u2²
Hence proved
Hope it helps dear friend ☺️✌️✌️
2as = v² - u²
Here v would be zero at maximum height. Hence v² = 0
=> 2as = -u²
s= -u²/2a
Height = s
Height of stone 1 :-
s1 = -u1²/-2g
Since a = -g
2a = -2g
Height of stone 2 :-
s2 =
ratio of s1 and s2 =
-u1²/-2g : -u2²/-2g
Cancelling -2g we have ratio =
-u1²: -u2²
Cancelling negative sign we have
u1² : u2²
Hence proved
Hope it helps dear friend ☺️✌️✌️
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