Question

Two stones are thrown with same speed u at different angles from ground in air. If both stones have same range and height attained by them are h1, and h2,
then h1 + h2, is equal to​

Answer 1

Answer:

the answer is in the attachment..

hope it helps you.

Answer 2

Answer:

The sum of height of both stone is $\dfrac{u^2}{2g}$

Explanation:

Given that,

Speed = u

Height of first stone = h₁

Height of second stone = h₂

Both stones have same range.

We need to calculate the height of first stone

Using formula of height

$h_{1}=\dfrac{u^2\sin^{2}\theta}{2g}$

We need to calculate the height of second stone

Using formula of height

$h_{2}=\dfrac{u^2\sin^{2}(90-\theta)}{2g}$

We need to calculate the sum of height of both stone

$h_{1}+h_{2}=\dfrac{u^2\sin^{2}\theta}{2g}+\dfrac{u^2\sin^{2}(90-\theta)}{2g}$

$h_{1}+h_{2}=\dfrac{u^2\sin^{2}\theta}{2g}+\dfrac{u^2\cos^{2}\theta}{2g}$

$h_{1}+h_{2}=\dfrac{u^2}{2g}$

Hence, The sum of height of both stone is $\dfrac{u^2}{2g}$