Question

Two stones having different masses m and m2 are projected at angles theta and theta(90°-theta) with same velocity from the same point. the ratio of their max.heights is​

Answer 1

Given :-

Two stones having different masses.

Mass of first stone = m

Mass of second stone = ${m}_{2}$

As we know that,

H = u² Sin²Ø/2g

H = u² Sin²Ø/2g

H' = u² Sin² (90° - Ø)/2g

Ratio = H/H'

H/H' = (u² Sin²Ø/2g)/u² Cos²Ø/2g

H/H' = u² Sin²Ø/2g × 2g/u² Cos²Ø

H/H' = Sin²Ø/Cos²Ø

H/H' = Tan²Ø

H:H' = Tan²Ø : 1

Hence,

The ratio of maximum height = H:H' = Tan²Ø:1.