Question

two stones having masses in ratio 3:2 are dropped from heights in ratio 4:9 .the ratio of magnitudes of their linear momenta just before reaching the ground is ? (neglect air resistance)

Answer 1

1:3here kinetic energy is equal to potential energy so mgh =half MV ^2 that is I can say mh is momentum

Answer 2

momentum=mass x velocity

momentum=?

mass = ratios are given

velocity=?

let us first findout velocity

v^2-u^2=2as

let velocity be v

since freely falling body    u=0

a=+g=9.8m/s2

s=h=4

by sloving

momentum        momentum

of                         of

first body            second body

v^2-0=2*9.8*4                   v^2-0=2*9.8*9

v^2=78.4                           v^2=176.4

v=8.8                                 v=13.2

given m ratios

mass                   mass

of                         of

1st body              2nd body

m=3                                   m=2

P=mv                       P=mv

P=3*8.8               P=2*13.2

P=26.4                 P=26.4

Ratios are 1:1