Two stones having masses in the ratio 3:2 are dropped from the heights in the ratio of4:9 . The ratio of magnitude of their linesr momenta just before reaching the ground is
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momentum p = mv = mh/t since v = h/t
p1/ p2 = m1/m2 × h1/h2 × t2/t1
taking t1 = t2 = t so both time will cancel out
p1 / p2 = 3/2×4/9
p1/p2 = 2/3.
ratio = 2:3. is the answerrr
p1/ p2 = m1/m2 × h1/h2 × t2/t1
taking t1 = t2 = t so both time will cancel out
p1 / p2 = 3/2×4/9
p1/p2 = 2/3.
ratio = 2:3. is the answerrr
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