Question

Two stones having masses in the ratio 3 is to 2 are dropped from the Heights in the ratio 4 is to 9 the ratio of magnitudes of the linear momentum just before reaching the ground is

Answer 1

given,

$\frac{m_{1}}{m_{2}} = \frac{3}{2}$

$\frac{h_{1}}{h_{2}} = \frac{4}{9}$

$p_{1}^{2} = m_{1}^{2}v_{1}^{2}$

$p_{1}^{2} = m_{1}^{2}(2ah_{1})$

$p_{2}^{2} = m_{2}^{2}v_{2}^{2}$

$p_{2}^{2} = m_{2}^{2}(2ah_{2})$

$(\frac{p_{1}}{p_{2}})^{2} = \frac{m_{1}^{2}h_{1}2a}{m_{2}^{2}h_{2}2a}$

$(\frac{p_{1}}{p_{2}})^{2} =  (\frac{3}{2})^{2} (\frac{4}{9})$

$p_{1}:p_{2} = 1:1$

Brainliest please